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NEW QUESTION: 1
Substitution method is to use a normal part of work to replace a suspect component is not working properly, so as to locate the fault, the fault here aim to exclude components, which can be a period of fiber optic patch cords, a cable, a controller or a cascade module.
A. True
B. False
Answer: A
NEW QUESTION: 2
VNet1およびVNet2という名前の2つの仮想ネットワークを含むAzureサブスクリプションがあります。 仮想マシンは仮想ネットワークに接続します。
仮想ネットワークには、次の表に示すように構成されたアドレススペースとサブネットがあります。
10.33.0.0/16のアドレススペースをVNet1に追加する必要があります。 ソリューションでは、VNet1とVNet2上のホストが通信できることを確認する必要があります。
順番に実行する必要がある3つのアクションはどれですか？ 回答するには、適切なアクションをアクションのリストから回答エリアに移動し、正しい順序に並べます。
Answer:
Explanation:
Explanation
Step 1: Remove peering between Vnet1 and VNet2.
You can't add address ranges to, or delete address ranges from a virtual network's address space once a virtual network is peered with another virtual network. To add or remove address ranges, delete the peering, add or remove the address ranges, then re-create the peering.
Step 2: Add the 10.44.0.0/16 address space to VNet1.
Step 3: Recreate peering between VNet1 and VNet2
References:
https://docs.microsoft.com/en-us/azure/virtual-network/virtual-network-manage-peering
NEW QUESTION: 3
View the Exhibit and examine the structure of the PRODUCTS tables.
You want to generate a report that displays the average list price of product categories where the average list price is less than half the maximum in each category.
Which query would give the correct output?
A. SELECT prod_category,avg(prod_list_price) FROM products GROUP BY prod_category HAVING avg(prod_list_price) > ANY (SELECT max(prod_list_price)/2 FROM products GROUP BY prod_category);
B. SELECT prod_category,avg(prod_list_price) FROM products HAVING avg(prod_list_price) < ALL (SELECT max(prod_list_price)/2 FROM products GROUP BY prod_category);
C. SELECT prod_category,avg(prod_list_price) FROM products GROUP BY prod_category HAVING avg(prod_list_price) > ANY (SELECT max(prod_list_price)/2 FROM products);
D. SELECT prod_category,avg(prod_list_price) FROM products GROUP BY prod_category HAVING avg(prod_list_price) < ALL (SELECT max(prod_list_price)/2 FROM products GROUP BY prod_category);
Answer: D
Explanation:
Using the ANY Operator in Multiple-Row Subqueries
The ANY operator (and its synonym, the SOME operator) compares a value to each value
returned by a subquery.
<ANY means less than the maximum.
>ANY means more than the minimum.
=ANY is equivalent to IN
Using the ALL Operator in Multiple-Row Subqueries
The ALL operator compares a value to every value returned by a subquery.
>ALL means more than the maximum and
<ALL means less than the minimum.
The NOT operator can be used with IN, ANY, and ALL operators.
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