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NEW QUESTION: 1
Which statements about an IPv6-over-IPv4 IPsec configuration are correct? (Choose two.)
A. The source quick mode selector must be an IPv4 address.
B. The local gateway IP must an IPv4 address.
C. The destination quick mode selector must be an IPv6 address.
D. The remote gateway IP must be an IPv6 address.
Answer: A,C

NEW QUESTION: 2
Firms with higher operating leverage tend to have _______ financial leverage.
A. same
B. lower
C. higher or lower (since the two are not related).
D. higher
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Firms with higher operating leverage have a higher fraction of costs in the form of fixed costs and hence, have a higher business risk. This makes them more averse to debt. Consequently, firms with higher operating leverage tend to have lower D/E ratios i.e. lower financial leverage.

NEW QUESTION: 3

A. Option A
B. Option B
C. Option D
D. Option C
Answer: D
Explanation:
Reference: http://en.wikipedia.org/wiki/Network_address_translation

NEW QUESTION: 4
You have a database that includes the following tables:

You need to create a list of all customer IDs and the date of the last order that each customer placed. If the customer has not placed any orders, you must return the date January 1, 1900. The column names must be CustomerID and LastOrderDate.
Which four Transact-SQL segments should you use to develop the solution? To answer, move the appropriate Transact-SQL segments from the list of Transact-SQL segments to the answer area and arrange them in the correct order.

Answer:
Explanation:

Explanation

Box 1: SELECT..COALESCE...
The COALESCE function evaluates the arguments in order and returns the current value of the first expression that initially does not evaluate to NULL.
Box 2: ..LEFT OUTER JOIN..
The LEFT JOIN (LEFT OUTER JOIN) keyword returns all rows from the left table (table1), with the matching rows in the right table (table2). The result is NULL in the right side when there is no match. A customer might have no orders so the right table must be allowed have a NULL value.
Box 3: ON c.custid = o.custid
We JOIN on the custID column, which is available in both tables.
Box 4: GROUP BY c.custid
References:
https://technet.microsoft.com/en-us/library/ms189499(v=sql.110).aspx
http://www.w3schools.com/sql/sql_join_left.asp

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